Question

solve this question and give the right answer​

Answer 1

Answer:

$log_{x}(8) = log_{4}(64) \\ = > log_{x}(8) = log_{4}( {8}^{2} ) \\ = > log_{x}(8) = 2 log_{4}(8) \\ = > x = \frac{4}{2} = 2 \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

this is the answer.. hope this helps... please thank and mark brainliest

Answer 2

$\rm\red{If \: log_x 8 = log_4 64 \: then \: x = }$

$\sf\underline{ \underline{identity \: regarding \: logarithm}} :$

$\sf log_{a}(b) = x \: \: then \\ \\ \sf \boxed{ \boxed{ \sf{a}^{x} = b}}$

$\rm \red{Then}$

$\rm \: log_x (8) = log_4( 64 ) \:$

$\sf \red{We \: know \: log_4 ( 64) =3}$

$\implies \rm log_{x}(8) = 3$

$\implies \rm {x}^{3} = 8$

$\implies \rm \: {x}^{3} = {2}^{3}$

$\boxed{ \boxed{\sf{ Powers \: are \: equal \: so \: bases \: should \: be \: equalised}}}$

$\implies \rm{ x = 2}$

$\boxed{ \boxed{\rm{If \: log_x( 8 )= log_4( 64) \: then \: x =2 }}}$