Math, asked by shaikhamedulla, 5 months ago

Solve this Question and show your answer... I'll mark you as Brainliest​

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Answered by mathdude500
1

\huge\pink{\boxed{\blue{\boxed{ \purple{ \boxed{{\pink{Answer}}}}}}}} \\ \large\pink{\boxed{\blue{\boxed{ \purple{ \boxed{{\pink{Your~answer↓}}}}}}}} \\ \small\bold\red{ \frac{ {a}^{ - 2} b( { {a}^{2} {b}^{ - 1} ) }^{4}( {a}^{ - 3}  {b}^{2} ) }{a {b}^{ - 2}  {( {a}^{ - 1}  {b}^{2}) }^{3}  {a}^{2} {b}^{3}  } } \\  =  \frac{ {a}^{ - 2} b{a}^{8}   {b}^{ - 4}  {a}^{ - 3} {b}^{2}  }{a {b}^{ - 2}  {a}^{ - 2} {b}^{6} {a}^{2}   {b}^{3}  }  \\  =  \frac{ {a}^{ - 2 + 8 - 3} {b}^{1 - 4 + 2}  }{ {a}^{1 - 2 + 2}  {b}^{ - 2 + 6 + 3} }  \\  =  \frac{ {a}^{3} {b}^{ - 1}  }{ {a}^{1} {b}^{7}  }  \\  =  {a}^{2}  {b}^{ - 8}  \\  =  {( {10}^{ - 3}) }^{2} {( -  {10}^{ - 2} )}^{ - 8}  \\  =  {10}^{ - 6}  \times  {10}^{16}  \\  =  {10}^{ - 6 + 16}  \\  =  {10}^{10}

Answered by kashishchaudhary64
0

abe oo tharki insaan me teri bestie itna maeungi kutte kamine

hammy the langoor rukja tu❌

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