Question

Solve this question as fast as you can.Best answer will be marked as brainliest...​

Answer 1

Answer:

hi!

in Δ AOB and Δ AOC :

OA=OC (DIAGONALS BISECT EACH OTHER )

OB=OB(COMMON SIDE)

∠AOB= ∠BOC (DIAGONALS BISECT EACH OTHER AT 90 DEGREE)

∴Δ AOB ≅ ΔBOC (S.A.S)

∴AB=AC (C.P.C.T)

SIMILARILY BY PROVING,Δ AOD ≅ ΔDOC AND Δ CD ≅ Δ AOD WE GET:

BC=CD AND CD=DA

∴AB=BC=CD=DA

i.e., ABCD IS A RHOMBUS

                                             ∴ HENCE PROVED