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Explanation:
Equivalence mass of iodine is 126.9 g
2Na 2 S 2 O 3 +I 2 →Na 2 S 4 O 6 +2NaI
The number of moles of iodine =0.5×
1000
46.3 ×0.124=0.002871 moles
The mass of iodine liberated is 0.002871×253.8=0.728 g.
The equivalent mass of metal x = the equivalent mass of iodine ×
mass of iodine liberated
mass of metal x liberated
=126.9× 0.728l0.617 =107.468
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