Question

solve this question as soon as possible. its too much imp. its from trignometrical identities chp 21 of 10th maths ICSE. best ans will be marked as brainliest and will get 5 thanks and follow from me on that particular ID. ​

Answer 1

Answer:

see the above attachment

Answer 2

Answer:

Step-by-step explanation:

rationalise the denominator i.e,

sina/1+cosa×1-cosa/1-cosa=sina(1-cosa)/(1+cosa)(1+cosa)

=sina-sina cosa/1-cos²a=sina-sina cosa/sin²a  [1-cos²a=sin²a]

=sina/sin²a-sina cosa/sin²a=1/sina-cosa/sina=coseca-cota

hence proved