Question

solve this question asap☝️​

Answer 1

ANSWER

see graph of sin function

or we can use dufferentiation method

derivative of sinx = cosx

put cosx = 0

x= (2n+1) π/2

where n € I set of integers

in range 0 to 4π

x = π/2, 3π/2 for n=0, 1

5π/2 greater then 4π

double derivative of sinx = - sinx

now π/2 lies in first quadrant and 3π/2 lies in third quadrant and sin function positive in 2nd quadrant and negative in third quadrant

we have double derivative = - sinx

so d2x/dx2 > 0 for x = 3π/2 minima

and

d2x/dx2 < 0 for x= π/2 maxima

hope it helps

follow me

bye