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sum of 4 angles of quadrilateral=360°
sum of opposite angles=180°
(2x-10)+y=180°.....I, (3x+20°)+65°=180°
;. =3x+20°+65°=180°
=3x+85°=180°
=3x=180°-85°
=x=95°/3
now putting x=95/3°
(2×95/3°)-10°+y=180°
=190/3°-10°+y=180°
=160°/3+y=180°
=y=180°-160/3°
y=380/3°
there ,I have solved it
I hope you will be getting helped. by my solution
Answered by
0
Answer:
x=15 y=20
Step-by-step explanation:
(1)3x+20=65
3x=65-20
3x=45
x=45÷3
x=15
(2)2x-10=y
2(15)-10=y
30-10=y
y=20
botanyliker:
opposite angles of any trapezium
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