solve this question by completing square method
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Answer: The zeroes are (√7+1 ±√8+6√7) /2
Step-by-step explanation:
We have,
x^2 -(√7 +1) x -√7 = 0
=>x^2 -(√7+1) x = √7
=>x^2 -(√7+1) x + ((√7+1) /2)^2 = √7 +((√7+1) /2) ^2 [Adding ((√7+1) /2)^2 on both sides]
=>{x - (√7+1) /2}^2 = √7 + (8+2√7) /4
=>{x - (√7+1) /2}^2 = (8+6√7) /4
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=>x - (√7+1) /2 = ±√(8+6√7)/2
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=> x = {√7+1 ±√(8+6√7) }/2
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