solve this question by splitting
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3√2x²+x-√2=0
3√2x²+3x-2x-√2=0
3x(√2x+1)-√2(√2x+1)=0
(3x-√2)(√2x+1)=0
3x-√2=0. and. √2x+1=0
x=√2/3. and. x=-1/√2
3√2x²+3x-2x-√2=0
3x(√2x+1)-√2(√2x+1)=0
(3x-√2)(√2x+1)=0
3x-√2=0. and. √2x+1=0
x=√2/3. and. x=-1/√2
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