Question

solve this question by substitution method class 10 ​

Answer 1

$2x - 3y = 1 \\ x = \frac{3y + 1}{2} ...(1) \\ \\ 3x - 4y = 1 \\ 3( \frac{3y + 1}{2} ) - 4y = 1 \\ 9y + 3 - 8y = 2 \\ y = - 1 \\ \\ (1) \implies \\ x = \frac{3( - 1) + 1}{2} \\ x = \frac{ - 3 + 1}{2} \\ x = - 1$