solve this question by using trigonometric identities.
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here is the another way to calculate the value of sec@
as we know.
sec^2@- tan^2@=1
(sec@+tan@) (sec@-tan@)=1............(1)
using a^2 - b^2=(a+b)(a-b)
sec@+tan@ =x
using eqn (1)
sec@ - tan@ =1/x...........(2)
add eqn 1 & eqn 2
2sec@=(x + 1/x)
:• sec@ = [1/2] (x+ 1/x)
as we know.
sec^2@- tan^2@=1
(sec@+tan@) (sec@-tan@)=1............(1)
using a^2 - b^2=(a+b)(a-b)
sec@+tan@ =x
using eqn (1)
sec@ - tan@ =1/x...........(2)
add eqn 1 & eqn 2
2sec@=(x + 1/x)
:• sec@ = [1/2] (x+ 1/x)
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