solve this question, Circles class 10 mathematics
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Answer:
angle cba=70 degree
Step-by-step explanation:
<PCB+<BCO+<OCA = 110............................eqn 1
<PCB+<BCO = 90.........................................eqn 2(radius OC perpendicular to PC)
<BCO+<OCA = 90.......................................eqn 3(angle subtented in a semicircle)
From eqn 1&2;<OCA =110 - 90=20 degree
In eqn 2; <BCO+<OCA = 90
<BCO =90 - 20 = 70 degree
OC = OB (radii of circle)
therefore;<BCO = <CBA
<CBA = 70 degree
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