Question

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Class---- 12th

Sub---Mathematics


Ch--- Inverse Trigonometric Function​

Answer 1

Answer:

${ \sec }^{ - 1} (2 \sin \frac{3\pi}{4} ) \\ \\ { \sec }^{ - 1} (2 \sin(\pi - \frac{\pi}{4} ))$

${ \sec }^{ - 1} (2 \sin( \frac{\pi}{4} ) ) \\ \\ { \sec }^{ - 1} (2 \times \frac{1}{ \sqrt{2} } ) \\ \\ { \sec }^{ - 1} ( \sqrt{2} )$

${ \sec }^{ - 1} ( \sec\frac{\pi}{4} ) \\ \\ \frac{\pi}{4}$

2nd step :-

sin (pi-Theta) = sin Theta

Sin (pi-pi/4) = sin pi/4

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