Question

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Answer 1

Answer:

The path is helix

Vsin60°gives circular path to the electron and Vcos60° moves the electron in the direction of GS

To reach point S, the minimum value of B is such that it completes one revolution and at the same time reaches point S

So time period for one revolution

T= 2πm/qB

, independent of velocity

Time required to cover distance

GS=T

GS=Vcos60×T

GS=Vcos60× 2πm/qB

We know that

KE= 1/2 mv²

v= ✓ 2(KE) / m

v= 2 ✓ 16 /91 × 10^15

=8.38×10^ 6 × ✓ 10

GS = 149.844/B × 10 ^ -6 × ✓10

B= =4.738×10 ^ −3T

Hope it helps you

Answer 2

Answer:

Hello....

Explanation:

Answer is 4.73×10^-3T.

STEPS ARE IN THE ABOVE ATTACHMENT.

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