Question

solve this question don't ans if you don't know ​

Answer 1

hope it's help me❤❤❤❤❤❤❤❤❤❤❤❤

Answer 2

$\implies\sf\large\red{\underline{ }} \frac{ {4}^{n + 1} . \: {2}^{n} - {8}^{n} }{ {2}^{3m} } = \frac{3}{8} \\ \\ \implies\sf\large\red{\underline{ }} \frac{ {( {2}^{2} )}^{n + 1} . {2}^{n} - { ({2}^{3}) }^{n} }{ {2}^{3m} } = \frac{3}{8} \\ \\ \implies \sf\large\red{\underline{ }} \frac{( {2}^{2n + 2} . \: {2}^{n}) - {2}^{3n} }{ {2}^{3m} } = \frac{3}{8} \\ \\ \implies\sf\large\red{\underline{ }} \frac{( {2}^{2n + 2 + n}) - {2}^{3n} }{ {2}^{3m} } = \frac{3}{8} \\ \\ \implies\sf\large\red{\underline{ }} \frac{ {2}^{3n + 2} \: \: - {2}^{3n} }{ {2}^{3m} } = \frac{3}{8} \\ \\ \implies\sf\large\red{\underline{ }} \frac{ {2}^{3n} (4 - 1)}{ {2}^{3m} } = \frac{3}{8} \\ \\ \implies\sf\large\red{\underline{ }} \frac{ {2}^{3n}(3) }{ {2}^{3m} } = \frac{3}{8} \\ \\ \implies\sf\large\red{\underline{ }} \frac{ {2}^{3n} }{ {2}^{3m} } = \frac{1}{ {2}^{3} } \\ \\ \implies\sf\large\red{\underline{ }} {2}^{3n} ( {2}^{3} ) = {2}^{3m} \\ \\ \implies\sf\large\red{\underline{ }} {2}^{3n + 3} = {2}^{3m} \\ \\ \implies\sf\large\red{\underline{ }}3n + 3 = 3m \\ \\ \sf{ dividing \: by \: 3 \: we \: get \: }.... \\ \\ \implies\sf\large\red{\underline{ n + 1 = m}} \\ \\ (proved)$