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Answer:
Hi mate here's your answer.
Step-by-step explanation:
Given that the sum of the first three terms is 45.
Also, given that the product of the first and third term is 200.
To find the three numbers.
Let the three numbers be a-b,a,a+ba−b,a,a+b
Sum of the three terms is 45
Thus, we have,
a-b+a+a+b=45a−b+a+a+b=45
3a=453a=45
a=15a=15
Thus, the value of a is 15
Product of the first and third term is 200.
Thus, we have,
(a-b)(a+b)=200(a−b)(a+b)=200
a^2-b^2=200a2−b2=200
15^2-b^2=200152−b2=200
225-b^2=200225−b2=200
b^2=25b2=25
b=5b=5
Thus, the value of b is 5.
Substituting the value of a and b in a-b,a,a+ba−b,a,a+b , we get,
15-5 , \ 15, \ 15+515−5, 15, 15+5
Simplifying, we have,
10,15,2010,15,20
Thus, the three numbers are 10,15,20
Hope you get it.
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Answer:
here is ur answer. . . . . . . . . . . . .
