Question

solve this question
don't give me any wrong answer than I'll report...
$4{x}^{2} - 4 {a}^{2}x + {a}^{4} - {b}^{4} = 0$
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Answer 1

Given:

$4{x}^{2} - 4 {a}^{2}x + {a}^{4} - {b}^{4} = 0$

To find:

To solve this

STEP BY STEP EXPLANATION:

$(2x - {a}^{2} {)}^{2} - {b}^{4}$

using ${a}^{2} - {b}^{2}$= (a - b)(a+b) factors the expression

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$(2x - {a}^{2} - {b}^{2} ) \times (2x - {a}^{2} - {b}^{2})$

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Hence verified !