Question

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Answer 1

Answer:

$\huge\color{blue}\boxed{\colorbox{lightgreen}{♧Solution♧}}\bigstar$

$y=∣x+2∣+∣x−3∣$

$case 1$

$Let x>3$

$y \: = \: x \: + \: 2 \: + \: x \: − \: 3,$

$y=2x−1,$

$y−2x=−1,$

$\frac{x}{ - 1} + \frac{x}{ \frac{1}{2} } = 1 \: \: \: \: \: \: \: \: case2$

$Let \: x \: <3 \: and \: x \: >−2$

$y=x+2−x+3,$

$y=5. \: \: \: \: \: \: case 3$

$Let \: \: x<−2$

$y= \: −x−2 \: − \: x+3,$

$y \: =−2x \: + \: 1,$

$y \: + \: 2x= \: 1.$

Thanks

Answer 2

Step-by-step explanation:

provided with three test tubes. One of them contains distilled water and the other two have an acidic solution and a basic solution respectively. If you are given only red litmus paper, how will you identify the contents of each test tube? 6. HCI, HNO, C,H,OH