Question

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remove the irrationality in the denominator.​

Answer 1

➠ Solution :-

$= > \sqrt{ \frac{ \sqrt{2} - 1}{ \sqrt{2} + 1 } } = \sqrt{ \frac{( \sqrt{2} - 1)( \sqrt{2} - 1) }{ (\sqrt{2} + 1)( \sqrt{2} - 1) } }$

$= > \sqrt{ \frac{2 + 1 - (2 \times \sqrt{2} \times 1) }{2 - 1} }$

$= > \sqrt{ \frac{3 - 2 \sqrt{2} }{1} }$

∴ The rationalized form of

$\sqrt{ \frac{ \sqrt{2} - 1 }{ \sqrt{2} + 1} }$

is

$\sqrt{3 - 2 \sqrt{2} }$

Answer 2

Step-by-step explanation:

The answer is this

$\bold\green{Hope this helps} \\ Brainliest Please$