Question

solve this question early​

Answer 1

Step-by-step explanation:

Given  in 1 4 7 and 1 8 9 one digit is right but in the wrong place and one digit is right and in the right place. So from the above options 1 is at the same place, so 1 is removed.

• Also from the digits 9  6  4, two digits are correct but both are in wrong place.
• Also in 5  2  3 all digits are wrong and so we need to remove or take out 5  2 and 3.
• Now in  2  8  6 one digit is right but in wrong place.
• So we have the numbers 1    8    9
•                                          9     6    4
•                                          2     8    6
• Now from numbers 9   6   4 , we get 9 is the correct number and is placed in the right position.
• Also from the numbers 1  4   7 and 9   6    4 we get 4 is in different position therefore 4 is wrong.
• Now from 1  4  7 the number 7 is the correct digit and placed at wrong position.
• Again if we take the same digits we get 8 to be in the same position and is wrong in another and so 8 is taken out.
• Now from numbers 2   8  6, the digit 6 is correct and also it cannot be in third place since there is 9. Also from numbers 9  6   4, the digit 6 cannot be at second position.
• Therefore 6 will be in first place and 7 in second place.
• Therefore the code will be 6  7  9

Reference link will be

https://brainly.in/question/16418439