Math, asked by santoshkumarrs8434, 7 months ago

solve this question fast.......

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Answers

Answered by arnav3375

1

Answer:

X3+y3-z3+3xyz

Step-by-step explanation:

let,

a. = x

b. = y

c. = -z

>. (a+b+c)(a2+b2+c2-ab-bc-ca)=A3+b3+c3-3abc

>. (x3+y3-2^3-3*x*y*c-2)

Therefore : x^3+y^3-z^3+3xyz

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