Question

Solve this question fast​

Answer 1

$\huge\it\blue{refer \: the \: attachment}$

Steps Followed

• Simplify LHS and RHS seperately

• In LHS use identity of
• ${(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab$
• Then cut sinA with cosecA with the identity of
• $coseca = \frac{1}{sina}$
• And cut cosA with secA with the identity of
• $seca = \frac{1}{cosa}$
• Then fill 1+cot^2A and 1+tan^2A in the place of cosec^2A and sec^2A respectively

• After simplify you will get 7+cot^2A+tan^2A

• We know that RHS is equal to 7+tan^2A+cot^2A

• LHS=RHS

• Hence proved