Question

solve this question fast

Answer 1

hey dude !


here is your answer

let the age of one of two friends be x yr.

then age of other friends=(20-x)yr

[the sum of the ages of two friends is 20yr]

4yr ago age of one of two friends =(x-4)yr

and age of the other friends (20-x-4)yr

=(16-x)yr


a/q

(x-4)(16-x)=48

16x-x^2-64+4x=48

x^2-20x+112=0


on comparing ax^2+bc+c=0

a=1, b= -20 c= 112


I hope help you

Answer 2

Answer:

heya were can I find @rishilaugh sir??