Question

solve this question fast!!!!​

Answer 1

1 is 60.5 2nd is 45.5 3rd is 19.5

Answer 2

area of llgm EDBA = b×h

7× 6.5

= 45.5cm²

Now, AB + BC = AC

( ED = AB )

ED + BC = 13

7 + BC = 13

BC = 13 -7

BC = 6

therefore ar(BDC) = 1/2 bh

1/2 × 6 × 6.5

(6.5 cuz ED II AB , there 6.5 is the height of the whole fig)

3×6.5

19.5cm²

Now, ar(EDCA) = ar(EDBA) + ar(DCB)

= 45.5+ 19.5

= 65 cm²

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