Question

solve this question fast and quick answer

Answer 1

Your Question
Find The Sum of First 123 Even Natural Numbers.
Answer
Even Number Have 2 difference in each

First Even Number(a)=2
Difference (d)=2
Total Numbers (n)=123

Sum Of Numbers=n/2(2a+(n-1)×d)
123/2(2×2+(123-1)×2)
=123/2(4+122×2)
=123/2(4+244)
=123/2×248
=123×124

Sum=15252

Answer 2

$\huge{\bold{\underline{\underline{Solution;}}}}$

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As we know that ,

Sum Of n natural even numbers =
$\frac{n(n + 2)}{2}$

Here,

n = 123

so, on substituting the value of n in the given formula we get,

$sum \: = \: \frac{123(123 +2)}{2} \\ \\ \\ \: \: \: \: \: \: \: \: \: \: \: = \frac{123 \times 125}{2} \\ \\ \: \: \: \: \: \: \: \: \: \: = 15252$

So, sum of 123 natural no is ,

$\bf{\huge{\boxed{15375}}}$

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