Question

solve this question fast if you're educated​

Answer 1

Answer:

$\begin{gathered}(3x + 4y - 5p) {}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ (3x \times 3x) + (4y \times 4y) +(5p \times 5p) \\ \tt \red{9x {}^{2} + 16y {}^{2} + 25p {}^{2} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \end{gathered}$

Answer 2

Answer:

Velocity Gradient = velocity × [distance]-1. Or, V = [M0 L1 T-1] × [M0 L1 T0]-1 = [M0 L0 T-1] Therefore, Velocity gradient is dimensionally represented as [M0 L0 T-1].