Question

Solve this question
fast need it urgently​

Answer 1

Answer:

P=(1,0);Q(−1,0)P=(1,0);Q(−1,0)

Let A=(x,y)A=(x,y)

APAQ=BPBQ=CPCQ=13...(1)APAQ=BPBQ=CPCQ=13...(1)

⇒3AP=AQ⇒9AP2=AQ2⇒9(x−1)2+9y2=(x+1)2+y2⇒3AP=AQ⇒9AP2=AQ2⇒9(x−1)2+9y2=(x+1)2+y2

⇒9x2−18x+9+9y2=x2+2x+1+y2⇒8x2−20x+8y2+8=0⇒9x2−18x+9+9y2=x2+2x+1+y2⇒8x2−20x+8y2+8=0

⇒x2+y2−52x+1=0...(2)⇒x2+y2−52x+1=0...(2)

∴∴ A lies on the circle

Similarly B, C are also lies on the same circle

∴∴ Circumcentre of ABC=ABC= Centre of Circle 

Answer 2

Answer:

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