Question

solve this question fast please​

Answer 1

Answer:

1 solution

✬ Ramesh age = 20 Years ✬

✬ Mahesh age = 28 Years ✬

Given:

Ratio of present ages of Ramesh and Mahesh is in ratio 5 : 7.

After 4 years their ages will be in ratio 3 : 4.

To Find:

What is the present ages of both ?

Solution: Let x be the common in given ratio. Therefore,

➼ Ramesh's age = 5x years

➼ Mahesh's age = 7x years

[ Now after 4 years their ages will be ]

➫ Ramesh age = 5x + 4 years

➫ Mahesh age = 7x + 4 years

A/q

After 4 years their ages will be in ratio 3 : 4

(5x + 4) : (7x + 4) = 3 : 4

(5x + 4)/(7x + 4) = 3/4

4(5x + 4) = 3(7x + 4)

20x + 16 = 21x + 12

20x – 21x = 12 – 16

–x = – 4

x = 4

So, Present ages are

➭ Ramesh age = 5x = 5(4) = 20 years

➭ Mahesh age = 7x = 7(4) = 28 years

2. solution

Given :

The addition of three successive multiples of 9 is 81.

To find:

The three multiples of 9.

Solution:

Let the consecutive multiples of 9 are 9x, 9(x+1), 9(x+2)

As it is given in the question that the sum of the multiples is 81 so,

9x+9(x+1)+9(x+2) = 81

9x+9x+9+9x+18 = 81

27x+27 = 81

27x = 81-27

27x = 54

x = 54/27

x = 2

so the multiple of 9 are given by:

9x = 9×2 = 18

9(x+1) = 9(2+1) = 9×3 = 27

9(x+2) = 9(2+2) = 9×4 = 36

The three consecutive multiples of 9 are 18, 27, and 36.

Step-by-step explanation:

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Answer 2

Answer

1. The present age of Ramesh is 20 years and that of Mahesh is 28 years

2. The required multiples of 9 are 18 , 27 , 36

Solution

1. Let us consider the present age of Ramesh be x years and that of Mahesh is y years

According to question

$\sf\implies \dfrac{x}{y} = \dfrac{5}{7} \\\\ \sf\implies x = \dfrac{5}{7} y$

Again by question

$\sf\implies \dfrac{x+4}{y+4} = \dfrac{3}{4} \\\\ \sf\implies 4(x + 4) = 3(y + 4) \\\\ \sf\implies 4(\dfrac{5}{7}y + 4) = 3y + 12 \\\\ \sf\implies \dfrac{20}{7}y + 16 = 3y + 12 \\\\ \sf\implies 3y - \dfrac{20}{7} y = 16-12 \\\\ \sf\implies \dfrac{21y-20y}{7} = 4 \\\\ \sf\implies y = 28$

Therefore , the present age of Mahesh is 28 years

Putting the value of y in (1)

$\sf\implies x = \dfrac{5}{7}\times 28 \\\\ \sf\implies x= 5\times 4 \\\\ \sf\implies x= 20$

Thus , the present age of Ramesh is 20 years .

_____________________

2. Let the three successive multiples be 9x , 9(x + 1) , 9(x + 2)

According to question

$\sf\implies 9x + 9(x + 1) + 9(x + 2) = 81 \\\\ \sf\implies 9(x + x + 1 + x +2) = 81 \\\\ \sf\implies 3x + 3 = 9 \\\\ \sf\implies 3x = 6 \\\\ \sf\implies x = 2$

Therefore, required multiples of 9 are

= 9×2 , 9×(2+1) , 9×(2+2)

= 18 , 27 , 36