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i) (2x + 1)³
(a + b)³ = a³+ b³+ 3ab(a + b)
(2x + 1)³ = 8x³ + 1 + 12x² + 6x
ii) (2a - 3b)³
(a – b)³ = a³–b³ – 3ab(a – b)
(2a – 3b)³ = (2a)³– (3b)³ – (3×2a×3b)(2a – 3b)= 8a³–27b³–36a²b + 54ab²
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