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Answer: 10+0root6 = 10
Step-by-step explanation:
(root3 - root2)/(root3 + root2) + (root3 + root2)/(root3 - root2)
Since denominators are different just take LCM
[Multiply 1st term by [root3-root2] && 2nd term by [rot3+root2]
(root3 - root2)*(root3-root2)/(root3 + root2)*(root3-root2) +
(root3 + root2)(root3+root2)/(root3 - root2)*(root3-root2)
= [(root3-root2)^2 + (root3+root2)^2] / 3-2
= 3+2-2root6+3+2+2root6/1
= 10
Given LHS = a+broot6
a = 10, b=0
Alternatively you can also rationalize the denominator and proceed
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