Question

solve this question fast solve 3

Answer 1

Given : tanx = 2

WKT, cotx = 1/tanx
So, cotx = 1/2

Using
${tan}^{2}x + 1 = sec {}^{2}x$
sec x = √5

WKT, cosx = 1/secx
So, cosx = 1/√5

Using
${sin}^{2} + {cos}^{2} = 1$
We get, sinx = 2/√5
WKT, cosecx = 1/sinx
So, cosec x = √5/2