Question

solve this question....↓
find the zeroes of the polynomial f(x)=4√3x²+5x-2√3 and verify the relation between zeroes and coefficients....

quick guys...!!
ans it fast...

Answer 1

4√3 x² + 5x - 2√3

x= -5 ± √25+96
-------------------
8√3
-5± 11
---------
8√3

-5+11. -5-11
------ , ---------
8√3. 8√3

3 / 4√3. , -2 / √3

let roots be alpha, beta

alpha+beta = -b/a
from eq. -5 / 4√3

3 /4√3 + (-2 / √3)
3 - 8 / 4√3. = -5/4√3

alpha x beta from eq. - 1/2
3/4√3 x -2/√3
-6/12 = -1/2

Simple

Answer 2

⭕❇Hey Mates !!!!!!!

➡➡Here is your answer ✔✔✔

➡Soln--

f(x)= 4√3x^2+5x-2√3

➡ 4√3x2 + 5x - 2√3 = 0

➡ 4√3x2 + 8x - 3x - 2√3 = 0

➡ 4x(√3x + 2) - √3(√3x + 2)

➡ (4x - √3)(√3x + 2)

➡ x = √3 / 4 , x= - 2/√3

❇❇❇❇❇❇❇❇❇❇❇❇❇❇❇❇❇❇❇❇❇❇

➡I hope this answer is helpful to you ☑☑☑

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