Question

Solve this question for me please

Answer 1

(x-b)(x-c)

(a-b)(a-c)

=x(x-c)-b(x-c)

a(a-c)-b(a-c)

=x²-cx-bx+bc

a²-ac-ab+bc

Then,

(x-c)(x-a)

(b-c)(b-a)

=x(x-a)-c(x-a)

b(b-a)-c(b-a)

=(x²-ax-cx+ac)

b²-ab-bc+ac

then,

(x-a)(x-b)

(c-a)(c-b)

=x(x-b)-a(x-b)

c(c-b)-a(c-b)

=x²-bx-ax+ab

c²-bc-ac+ab

plzz mark me as brainliest...