solve this question for me plzz
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a=√3+1/√3-1
= (√3+1)^2/3-1
=(√3+1)^2/2
= 4+2 √3/2
=2+√3
b=1/a=1/2+√3
=2-√3
a^2-b^2+ab =(a-b)(a+b)+ab
=2√3(4)+(4-3)
=8√3+1
= (√3+1)^2/3-1
=(√3+1)^2/2
= 4+2 √3/2
=2+√3
b=1/a=1/2+√3
=2-√3
a^2-b^2+ab =(a-b)(a+b)+ab
=2√3(4)+(4-3)
=8√3+1
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