Question

Solve this question frnds tomorrow is my exam

Answer 1

Join AO .
Angle ADO = 90 .
by Pythagoras theorem.
(hyp) square = 9+16 = 25. so radius = root 25 = 5 cm.

Answer 2

first draw OA
AB=6CM
So, AD=3cm
OD = 4cm
and ∆ ADO=90
SO,
(OA)^2=(OD)^2+(AD)^2 [ theory of Pythagoras]
(OA)^2= (4)^2+(3)^2
(OA)^2= 16+9
(OA)^2=25
OA=√25
OA=5

OA is radius of cercle.
So, Radius of Cercle = 5cm

this is your answer.....

I hope it helps you......