solve this question from class 9 circles maths, NO SPAMMING OR YOU WILL GET REPORTED AND BANNED.
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Given, ∠AOB=110
∘
In △AOB
OA=OB (Radius of the circle)
Thus, ∠OAB=∠OBA (Isosceles triangle property)
Sum of angles of the triangle = 180
∠AOB+∠OAB+∠OBA=180
110+2∠OBA=180
∠OBA=35
∘
Since, PQ is a tangent touching the circle at B.
Thus, ∠OBQ=90
∘
Now, ∠ABQ+∠OBA=90
∠ABQ+35=90
∠ABQ=55
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