Question

solve this question from quadratic equation .​

Answer 1

Answer:

-3

Step-by-step explanation:

Given Equation is 2x³ + x² - 7 = 0

On comparing with ax³ + bx² + cx + d = 0, we get

a = 2, b = 1, c = 0, d = -7

Now,

(i) α + β + γ = -b/a

                   = -1/2

(ii) αβ + βγ + αγ = c/a

                         = 0

(iii) αβγ = -d/a

            = 7/2

On dividing (2) by (3), we get

⇒ (αβ + βγ + γα)/αβγ = 0

⇒ 1/α + 1/β + 1/γ = 0

Then:

1/α + 1/β = -1/γ

1/β + 1/γ = -1/α

1/γ + 1/α = -1/β

Now,

Given: ∑(α/β + β/α)

= α/β + β/α + β/γ + γ/α + γ/β + α/γ

= α(1/β + 1/γ) + β(1/γ+1/α) + γ(1/α+1/β)

= α(-1/α) + β(-1/β) + γ(-1/γ)

= -1 - 1 - 1

= -3

Hope it helps!

Answer 2

Answer:

answer÷

-3

Step-by-step explanation:

hope it help you