Math, asked by Mbappe007, 1 month ago

Solve this question from the image ​

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Answered by Anonymous
5

Answer :

( 1 - cos A)/ sin A

Multiplying both numerator and denominator by ( 1 + cos A)

= ( 1 - cos A)( 1 + cos A ) / sin A( 1 + cos A)

Using algebraic identity ( x + y)( x - y) = x² - y² we get

= ( 1 - cos² A) / sin A( 1 + cos A)

Using trignometric identity, 1 - cos² A = sin² A we get

= sin² A / sin A( 1 + cos A)

= sin A / ( 1 + cos A)

Therefore the answer is option ( b)

Answered by sohamc060
1

Answer:

(1- cos A/ sin A

Multiplying both numerator and denominator

by (1+ cosA)

= (1 cos AX 1t cos A)/ sin A(1+ cos A)

Using algebraic identity (x + y(x - y) = x- y

we get

= (1- cos A)/ sin A(1+ cos A)

Using trignometric identity, 1 - cos A = sin^ A

we get

sin A/ sin A(1+ cos A)

sin A/(1+ cos A)

Therefore the answer is option (B)

Step-by-step explanation:

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