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Answers
Answer :
( 1 - cos A)/ sin A
Multiplying both numerator and denominator by ( 1 + cos A)
= ( 1 - cos A)( 1 + cos A ) / sin A( 1 + cos A)
Using algebraic identity ( x + y)( x - y) = x² - y² we get
= ( 1 - cos² A) / sin A( 1 + cos A)
Using trignometric identity, 1 - cos² A = sin² A we get
= sin² A / sin A( 1 + cos A)
= sin A / ( 1 + cos A)
Therefore the answer is option ( b)
Answer:
(1- cos A/ sin A
Multiplying both numerator and denominator
by (1+ cosA)
= (1 cos AX 1t cos A)/ sin A(1+ cos A)
Using algebraic identity (x + y(x - y) = x- y
we get
= (1- cos A)/ sin A(1+ cos A)
Using trignometric identity, 1 - cos A = sin^ A
we get
sin A/ sin A(1+ cos A)
sin A/(1+ cos A)
Therefore the answer is option (B)
Step-by-step explanation:
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