Question

solve this question ghdg​

Answer 1

$\tt \: \frac{ 3x-8 }{ 2x-11 } = \frac{ 3x+11 }{ 2x+8 }$

• Variable x cannot be equal to any of the values -4,$\tt \:\frac{11}{2}$since division by zero is not defined. Multiply both sides of the equation by $\tt \:2\left(2x-11\right)\left(x+4\right)$, the least common multiple of 2x-11,2x+8.

$\tt \: \left(2x+8\right)\left(3x-8\right)=\left(2x-11\right)\left(3x+11\right)$

• Use the distributive property to multiply 2x+8 by 3x-8 and combine like terms.

$\tt \: 6x^{2}+8x-64=\left(2x-11\right)\left(3x+11\right) \\ \tt \: 6x^{2}+8x-64=6x^{2}-11x-121 \\ \tt \: 6x^{2}+8x-64-6x^{2}=-11x-121 \\ \tt \:8x-64=-11x-121 \\ \tt \: 8x-64+11x=-121 \\ \tt \: 19x-64=-121 \\ \tt \: 19x=-57 \\ \tt \: x=\frac{-57}{19} \\ \tt \: x=-3$

$\sf \: @WildCat7083$

Answer 2

Ref image.

hope you can understand my handwriting :)