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Answer:Answer is 1.5 ev
Explanation:
Given , threshold wavelength , λ₀ = 380nm
wavelength of incident light , λ = 260nm
Using , einstein's relation of photoelectric effect
(KE)max = ev₀ = hv - hv₀ _______(i)
but, hv = E = 1237/λ(nm) ev (given)
and E₀ = 1237 / λ₀ (nm) ev
∴From (i) we get ,
(KE)max = E - E₀ (1237/λ - 1237/λ₀) ev
= 1237 ( 1/λ - 1/λ₀) ev (λ in nm) _______(iii)
By putting value of λ and λ₀ in eq (i) . (iii) , we get
(KE)max = 1237(1/260-1/380)ev
= 1237 × (380-260/380×260) ev
= (KE)max = 1.5ev
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