Question

solve this question guys I'll give you brain mark​

Answer 1

c) Twice the Pth term..

Answer 2

Answer:

AP is equal to Twice the pth term.

Step-by-step explanation:

Let say first term = a

Common difference = d

(p+q) th term = a + (p+q-1)d

(p-q) th term = a + (p=q-1)d

pth term = a + (p-1)d

Sum of (p+q) th term & (p-q) th term

(p+q) th term + (p-q) th term = a + (p+q-1)d + a + (p-q-1)d

= a + pd + qd - d + a + pd -qd -d

= 2a + 2pd - 2d

= 2(a + pd -d)

= 2(a + (p-1)d)

= 2 pth term

Therefore,

AP is equal to Twice the pth term.

Hope it helps!