Question

Solve this question guys of 26th question

Answer 1

Let R be the resistance of the electric lamp.

In series total resistance =R1 + R2

=5 + R

I=V/R

1 = 10/5+R

R = 5 ohm

Part 2:

Total Resistance =

= 100/20= 5ohm

Current in each branch=2/2

= 1 Amp (since both branches have same resistances, current divides equally)

V across Lamp + conductor = 10 V

V across Lamp = I × R = 1 × 5 = 5 Volt