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Let,
Angle A = x and Angle B = y
As mentioned in the question angle C = 3 angle B = 3y
Angle C is also given as 2(Angle A + Angle B) = 2(x+y)
So,
➟ 3y = 2(x+y)
➟ y = 2x
So angle C = 3y = 6x
We know that sum of all the 3 angles in a triangle = 180°
Therefore,
➟ Angle A+ Angle B + Angle C = 180
➟ x+ 2x+ 6x = 180
➟ x = 20
Hence,
Angle A = 20
Angle A = 20Angle B = 40
Angle A = 20Angle B = 40Angle C = 120
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