Question

Solve this question help pls ​

Answer 1

Answer:

B) 10/3 (left)

Step-by-step explanation:

Given:

Mass of 1st body (m1)= 10kg

Mass of 2nd object (m2) = 5kg

Velocity of 1st body (v1)= 5m/s

Velocity of 2nd body(v2)=20m/s

Momentum of first body(p1)= m1×v1

= 10kg ×5m/s

= 50kg.m/s

And, momentum of second body(p2)= m2×v2

= 5kg×20m/s

=100kg.m/s

Now, on collision, resultant momentum(p3)

= m2v2-m1v1

=100kg.m/s - 50kg.m/s

= 50kg.m/s

And, new mass(m3) = m1+m2.

[As two bodies stick with each other on collision]

=10kg+5kg

=15kg

Now, the new momentum(p3) =m3× velocity(v3)

=> 50kg.m/s = 15kg× v3

=> (50kg.m/s)/15kg= v3

=> v3= 10/3m/s

Asmomentum of 2nd body was more. So, the bodies after collision will move to left.

So, option (b) is correct.

PLEASE MARK ME AS BRAINLIEST