Math, asked by mansiyuvrajbansode30, 5 hours ago

solve this question

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Answered by BRAINLYARMY001
1

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Answered by savnijain6032
1

Answer:

Step-by-step explanation:

(7xy + 4y²) × (3y² + 8x²)

First we will find the product

7xy (3y² + 8x²) + 4y² (3y² + 8x²)

= 21xy³ + 56x³y + 12y4 + 32x²y²

Now if x = 1

So to make it short lets put this value in the product of both the expressions

21xy³ + 56x³y + 12y4 + 32x²y²

21y³ (1) + 56y (1)³ + 12y4 + 32y² (1)²

= 21y³ + 56y + 12y4 + 32y²

So when we will put value as x so the answer would be 21y³ + 56y + 12y4 + 32y²

Now if y = 2

So to make it short lets put this value in the product of both the expressions

21xy³ + 56x³y + 12y4 + 32x²y²

= 21x (2)³ + 56x³ (2) + 12 (2)4 + 32x² (2)²

= 168x + 112x³ + 192 + 128x²

May the answer will help you!!

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