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two equal sides +x =50
26+x=50
x=24
area =0.5*24*h
26+x=50
x=24
area =0.5*24*h
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Given that one of the equal sides of an isosceles triangle = 13cm.
Let the other side be x cm.
Given that perimeter = 50cm.
13 + 13 + x = 50
26 + x = 50
x = 50 - 26
x = 24cm.
Therefore the third side = 24cm.
By Pythagoras theorem, we get
12^2 + height^2 = 13^2.
144 + height^2 = 169
Height^2 = 169 - 144
Height^2 = 25
height = 5cm.
We know that Area of triangle = 1/2 * b * h
= 1/2 * 24 * 5
= 60cm^2.
Hope this helps!
Let the other side be x cm.
Given that perimeter = 50cm.
13 + 13 + x = 50
26 + x = 50
x = 50 - 26
x = 24cm.
Therefore the third side = 24cm.
By Pythagoras theorem, we get
12^2 + height^2 = 13^2.
144 + height^2 = 169
Height^2 = 169 - 144
Height^2 = 25
height = 5cm.
We know that Area of triangle = 1/2 * b * h
= 1/2 * 24 * 5
= 60cm^2.
Hope this helps!
siddhartharao77:
If possible brainliest it..
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