solve this Question I will follow that person and mark as braniest
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In triangle AMO And BNO
ANGLE M=N(90EACH)
OA=OB(GIVEN)
ANGLE A=ANGLE B(ALTERNATE ANGLES)
TRIANGLE AMO IS CONGRUENT TO TRIANGLE BNO
AN=BN(BY CPCT)
ANGLE M=N(90EACH)
OA=OB(GIVEN)
ANGLE A=ANGLE B(ALTERNATE ANGLES)
TRIANGLE AMO IS CONGRUENT TO TRIANGLE BNO
AN=BN(BY CPCT)
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