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If sin a = 1/3, then find the value of
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Answer:sin theta=1÷3, cos^2 theta =1-1÷9={8÷9} then cot^2theta=cos^2theta÷sin^2theta=8, 2cot^2theta+2=2×8+2=18
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ÅhØy ❤
sin theta = 1/3
cos²theta =1-1/9
= (8/9)
cot²theta = cos²theta / sin²theta = 8*2cot²theta +2
= 2*8+2
= 18
HöPe ïT hèLps ‼
sin theta = 1/3
cos²theta =1-1/9
= (8/9)
cot²theta = cos²theta / sin²theta = 8*2cot²theta +2
= 2*8+2
= 18
HöPe ïT hèLps ‼
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