Question

Solve this question if you can.​

Answer 1

Given that az3+ 4z2 + 3z - 4and z3 - 4z + a leave the same remainder when divided by z - 3 Hence [a(3)3+ 4(3)2 + 3(3) - 4] = [(3)3 - 4(3) + a] ⇒ [27a+ 36 + 9 - 4] = [27 -12 + a] ⇒ [27a+ 41] = [15 + a] ⇒ 26a = – 26 Hence a = – 1

Answer 2

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