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Step-by-step explanation:
11 players can be selected out of 16 in 16C11 ways = 16!/(11! 5!) = 4368 ways. Now,
If two particular players is to be included and one particular player is to be rejected, then we have to select 9 more players out of 13 in 13C9 ways.
= 13!/(9! 4!) = 715 ways.
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